What is the solution for 2sin(2x)dx+3e^{3y}dy=2xdx ?

The solution for 2sin(2x)dx+3e^{3y}dy=2xdx is y=(ln(x^2+cos(2x)+c_{1}))/3

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2sin(2x)dx+3e^{3y}dy=2xdx

2 sin (2 x) d x + 3 e^{3 y} d y = 2 x d x

y = \frac{ln ( x ^{2} + cos ( 2 x ) + c _{1} )}{3}

Solution steps

2 sin (2 x) d x + 3 e^{3 y} d y = 2 x d x

Solve separable ODE:

y = \frac{ln ( x ^{2} + cos ( 2 x ) + c _{1} )}{3}

y = \frac{ln ( x ^{2} + cos ( 2 x ) + c _{1} )}{3}

\int_{- 2}^{- 1} x^{2} - x - 2 d x

\frac{d y}{d x} = \frac{3 x + 2 y}{3 x + 2 y + 2}

y^{^{''}} + 7 y^{^{'}} + 10 y = - 4 sin (3 t)

sin^{2} (3 x)

f (x) = (6 x - 2)^{\frac{1}{4}}, at x = 1

What is the solution for 2sin(2x)dx+3e^{3y}dy=2xdx ?
The solution for 2sin(2x)dx+3e^{3y}dy=2xdx is y=(ln(x^2+cos(2x)+c_{1}))/3