What is the derivative of 8/t ?

The derivative of 8/t is -8/(t^2)

What is the first derivative of 8/t ?

The first derivative of 8/t is -8/(t^2)

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derivative of

\frac{8}{t}

- \frac{8}{t ^{2}}

Solution steps

\frac{d}{d t} (\frac{8}{t})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 8 \frac{d}{d t} (\frac{1}{t})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 8 \frac{d}{d t} (t^{- 1})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 8 (- 1 \cdot t^{- 1 - 1})

Simplify

8 (- 1 \cdot t^{- 1 - 1}) : - \frac{8}{t ^{2}}

= - \frac{8}{t ^{2}}

\int x sin (x) cos (x) d x

\frac{d}{d x} ((2 - x)^{2})

\frac{\partial}{\partial x} (4 x y - 10 x^{2} y^{2} z + 5 z^{2})

y^{\frac{4}{5}}

x \to 1 - lim (\frac{2 x}{x ^{3} - 1})