What is the solution for 1/((y^2-3y+2))y^'= 1/x ?

The solution for 1/((y^2-3y+2))y^'= 1/x is y=-(e^{c_{1}}x)/(1-e^{c_{1)}x}+2/(1-e^{c_{1)}x}

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1/((y^2-3y+2))y^'= 1/x

\frac{1}{( y ^{2} - 3 y + 2 )} y^{^{'}} = \frac{1}{x}

y = - \frac{e ^{c_{1}} x}{1 - e ^{c_{1}} x} + \frac{2}{1 - e ^{c_{1}} x}

Solution steps

\frac{1}{( y ^{2} - 3 y + 2 )} y^{'} (x) = \frac{1}{x}

Solve separable ODE:

y = - \frac{e ^{c_{1}} x}{1 - e ^{c_{1}} x} + \frac{2}{1 - e ^{c_{1}} x}

y = - \frac{e ^{c_{1}} x}{1 - e ^{c_{1}} x} + \frac{2}{1 - e ^{c_{1}} x}

x \to 3 lim (x - 10)

x \to - a lim (f (x))

\frac{d y}{d x} + \frac{3 y}{x} = - \frac{1}{x}

\int cos^{4} (x) sin (d) x d x

\int \frac{1}{x ^{\frac{3}{2}}} d x

What is the solution for 1/((y^2-3y+2))y^'= 1/x ?
The solution for 1/((y^2-3y+2))y^'= 1/x is y=-(e^{c_{1}}x)/(1-e^{c_{1)}x}+2/(1-e^{c_{1)}x}