What is area xy=24,2x^2-y^2+4=0 ?

The answer to area xy=24,2x^2-y^2+4=0 is No Solution

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area xy=24,2x^2-y^2+4=0

area

x y = 24, 2 x^{2} - y^{2} + 4 = 0

No Solution

Solution steps

Isolate

y

for

x y = 24 : y = \frac{24}{x}; x \neq = 0

Isolate

y

for

2 x^{2} - y^{2} + 4 = 0 : y = 2 x^{2} + 4, y = - 2 x^{2} + 4

f_{1} (x) = \frac{24}{x}

f_{2} (x) = 2 x^{2} + 4

To find the intersection points solve

f_{i} (x) = f_{j} (x)

\frac{24}{x} = 2 x^{2} + 4 : x = 4

\frac{24}{x} = - 2 x^{2} + 4 : x = - 4

2 x^{2} + 4 = - 2 x^{2} + 4 :

No Solution for

x \in R

Curves not bounded

= No Solution

\frac{d y}{d x} = \frac{x ^{2}}{10 y} - \frac{2 x}{5 y}

\frac{4}{3} π r^{3}

\frac{s - s}{s ^{2}}

y = 3 - x^{2}, y = - 1

\int_{a}^{b} \frac{1}{r ^{2}} d r

What is area xy=24,2x^2-y^2+4=0 ?
The answer to area xy=24,2x^2-y^2+4=0 is No Solution