What is (\partial)/(\partial u)(sin(u)cos(v)) ?

The answer to (\partial)/(\partial u)(sin(u)cos(v)) is cos(v)cos(u)

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(\partial)/(\partial u)(sin(u)cos(v))

\frac{\partial}{\partial u} (sin (u) cos (v))

cos (v) cos (u)

Solution steps

\frac{\partial}{\partial u} (sin (u) cos (v))

Treat

v

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= cos (v) \frac{\partial}{\partial u} (sin (u))

Apply the common derivative:

\frac{\partial}{\partial u} (sin (u)) = cos (u)

= cos (v) cos (u)

\frac{d y}{d x} = e^{y} sin (x)

\frac{d}{d x} (\frac{x ^{2}}{6 + x})

f (x) = \frac{1}{x + 2}, at x = 3

\frac{\partial}{\partial x} (\frac{1}{1 - x ^{4}})

(3 + x) d x = (e^{t} - e^{- t}) d t

What is (\partial)/(\partial u)(sin(u)cos(v)) ?
The answer to (\partial)/(\partial u)(sin(u)cos(v)) is cos(v)cos(u)