What is the derivative of e^{sin(x}-1) ?

The derivative of e^{sin(x}-1) is e^{sin(x)}cos(x)

What is the first derivative of e^{sin(x}-1) ?

The first derivative of e^{sin(x}-1) is e^{sin(x)}cos(x)

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\frac{d}{d x} (e^{s i n (x)} - 1)

e^{s i n (x)} cos (x)

Solution steps

\frac{d}{d x} (e^{s i n (x)} - 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (e^{s i n (x)}) - \frac{d}{d x} (1)

\frac{d}{d x} (e^{s i n (x)}) = e^{s i n (x)} cos (x)

\frac{d}{d x} (1) = 0

= e^{s i n (x)} cos (x) - 0

Simplify

= e^{s i n (x)} cos (x)

\int_{3}^{13} x d x

\int sin^{5} (x) cos^{5} (x) d x

x \to - 9 - lim (x^{2} - 81)

\int 2 x^{2} cos (m x) d x

x \to - 3 lim (4 x^{2} + 2 x - 1)

What is the derivative of e^{sin(x}-1) ?
The derivative of e^{sin(x}-1) is e^{sin(x)}cos(x)
What is the first derivative of e^{sin(x}-1) ?
The first derivative of e^{sin(x}-1) is e^{sin(x)}cos(x)