What is the derivative of y=ln(x-9) ?

The derivative of y=ln(x-9) is 1/(x-9)

What is the first derivative of y=ln(x-9) ?

The first derivative of y=ln(x-9) is 1/(x-9)

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derivative of

y = ln (x - 9)

\frac{1}{x - 9}

Solution steps

\frac{d}{d x} (ln (x - 9))

Apply the chain rule:

\frac{1}{x - 9} \frac{d}{d x} (x - 9)

= \frac{1}{x - 9} \frac{d}{d x} (x - 9)

\frac{d}{d x} (x - 9) = 1

= \frac{1}{x - 9} \cdot 1

Simplify

= \frac{1}{x - 9}

\int_{0}^{1} \frac{2 x}{1 + x ^{2}} d x

\frac{d ^{2}}{d x ^{2}} (2 x^{3} - x)

\int 4 x 4 - x^{2} d x

\frac{\partial}{\partial x} (x y + yz + z x - 3)

y = e^{2 x}, at x = \frac{1}{2} ln (2)

What is the derivative of y=ln(x-9) ?
The derivative of y=ln(x-9) is 1/(x-9)
What is the first derivative of y=ln(x-9) ?
The first derivative of y=ln(x-9) is 1/(x-9)