What is the derivative of (x^2+1^6) ?

The derivative of (x^2+1^6) is 12x(x^2+1)^5

What is the first derivative of (x^2+1^6) ?

The first derivative of (x^2+1^6) is 12x(x^2+1)^5

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\frac{d}{d x} ((x^{2} + 1)^{6})

12 x (x^{2} + 1)^{5}

Solution steps

\frac{d}{d x} ((x^{2} + 1)^{6})

Apply the chain rule:

6 (x^{2} + 1)^{5} \frac{d}{d x} (x^{2} + 1)

= 6 (x^{2} + 1)^{5} \frac{d}{d x} (x^{2} + 1)

\frac{d}{d x} (x^{2} + 1) = 2 x

= 6 (x^{2} + 1)^{5} \cdot 2 x

Simplify

= 12 x (x^{2} + 1)^{5}

(x^{2} + 2 x y + y^{2}) d x + (2 x y + x^{2} - 1) d y = 0

30 ln (3 x + 1)

y = (4 x^{2} - 8 x + 8) e^{- 4 x}

\frac{\partial}{\partial x} (ln (x + 9 y + 8 z))

\frac{\partial}{\partial x} (x y^{2} z^{4})

What is the derivative of (x^2+1^6) ?
The derivative of (x^2+1^6) is 12x(x^2+1)^5
What is the first derivative of (x^2+1^6) ?
The first derivative of (x^2+1^6) is 12x(x^2+1)^5