What is the solution for 10000y^{''}-81y=0,y(0)=1,y^'(0)=3 ?

The solution for 10000y^{''}-81y=0,y(0)=1,y^'(0)=3 is y=(1+97/6)e^{(9t)/(100)}-97/6 e^{-(9t)/(100)}

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10000y^{''}-81y=0,y(0)=1,y^'(0)=3

10000 y^{^{''}} - 81 y = 0, y (0) = 1, y^{^{'}} (0) = 3

y = (1 + \frac{97}{6}) e^{\frac{9 t}{100}} - \frac{97}{6} e^{- \frac{9 t}{100}}

Solution steps

10000 y^{''} (t) - 81 y = 0

Solve linear ODE:

y = (1 + \frac{97}{6}) e^{\frac{9 t}{100}} - \frac{97}{6} e^{- \frac{9 t}{100}}

y = (1 + \frac{97}{6}) e^{\frac{9 t}{100}} - \frac{97}{6} e^{- \frac{9 t}{100}}

\frac{\partial}{\partial y} (\frac{y ^{3}}{x ^{2}})

y^{^{'}} = - k y^{3}

\int (\frac{1}{x} + cot (x) - sec (x)) d x

e^{3 \cdot x} \cdot (2 \cdot sin (4 \cdot x))

\int \frac{1}{( 2 y + 5 ) ^{2}} d y

What is the solution for 10000y^{''}-81y=0,y(0)=1,y^'(0)=3 ?
The solution for 10000y^{''}-81y=0,y(0)=1,y^'(0)=3 is y=(1+97/6)e^{(9t)/(100)}-97/6 e^{-(9t)/(100)}