What is the derivative of y=2(6x^2-42x+49) ?

The derivative of y=2(6x^2-42x+49) is 2(12x-42)

What is the first derivative of y=2(6x^2-42x+49) ?

The first derivative of y=2(6x^2-42x+49) is 2(12x-42)

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derivative of

y = 2 (6 x^{2} - 42 x + 49)

2 (12 x - 42)

Solution steps

\frac{d}{d x} (2 (6 x^{2} - 42 x + 49))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (6 x^{2} - 42 x + 49)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= 2 (\frac{d}{d x} (6 x^{2}) - \frac{d}{d x} (42 x) + \frac{d}{d x} (49))

\frac{d}{d x} (6 x^{2}) = 12 x

\frac{d}{d x} (42 x) = 42

\frac{d}{d x} (49) = 0

= 2 (12 x - 42 + 0)

Simplify

= 2 (12 x - 42)

f (x) = 25 x

\int_{1}^{e} 3 x^{2} ln (x) d x

f (x) = 3 x^{\frac{1}{2}}

\frac{\partial}{\partial y} (x y - x^{2} y)

\int 4 e^{- 0.8 x} d x

What is the derivative of y=2(6x^2-42x+49) ?
The derivative of y=2(6x^2-42x+49) is 2(12x-42)
What is the first derivative of y=2(6x^2-42x+49) ?
The first derivative of y=2(6x^2-42x+49) is 2(12x-42)