What is the derivative of cos(x+y) ?

The derivative of cos(x+y) is -sin(x+y)

What is the first derivative of cos(x+y) ?

The first derivative of cos(x+y) is -sin(x+y)

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derivative of

cos (x + y)

- sin (x + y)

Solution steps

\frac{d}{d x} (cos (x + y))

Treat

y

as a constant

Apply the chain rule:

- sin (x + y) \frac{d}{d x} (x + y)

= - sin (x + y) \frac{d}{d x} (x + y)

\frac{d}{d x} (x + y) = 1

= - sin (x + y) \cdot 1

Simplify

= - sin (x + y)

\int \frac{t}{t - 1} d t

\frac{d}{d x} (csc (5 x))

y = 3 lo g_{7} (x^{2} + 1)

\frac{d y}{d x}, 7 x^{2} - 280 x + y^{2} + 174 = 0

\frac{d}{d x} (sin (x) e^{c o s (x)})

What is the derivative of cos(x+y) ?
The derivative of cos(x+y) is -sin(x+y)
What is the first derivative of cos(x+y) ?
The first derivative of cos(x+y) is -sin(x+y)