What is the tangent of y= 1/(x^2),(2, 1/4) ?

The tangent of y= 1/(x^2),(2, 1/4) is y=-1/4 x+3/4

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tangent of y= 1/(x^2),(2, 1/4)

tangent of

y = \frac{1}{x ^{2}}, (2, \frac{1}{4})

y = - \frac{1}{4} x + \frac{3}{4}

Solution steps

Find the slope of

y = \frac{1}{x ^{2}} : \frac{d y}{d x} = - \frac{2}{x ^{3}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - \frac{1}{4}

Find the line with slope m=

- \frac{1}{4}

and passing through

(2, \frac{1}{4}) : y = - \frac{1}{4} x + \frac{3}{4}

y = - \frac{1}{4} x + \frac{3}{4}

(t + 1)^{^{'}}

\int \frac{8}{x ( x + 2 )} d x

x \to 0 lim (\frac{sin ^{2} ( 5 x )}{x})

e^{- 9 x}, 0

t^{2} (8 e^{2 t} - 6 sin (2 t))

What is the tangent of y= 1/(x^2),(2, 1/4) ?
The tangent of y= 1/(x^2),(2, 1/4) is y=-1/4 x+3/4