What is the derivative of x^2-39.5x+120+(125/x) ?

The derivative of x^2-39.5x+120+(125/x) is 2x-(125)/(x^2)-39.5

What is the first derivative of x^2-39.5x+120+(125/x) ?

The first derivative of x^2-39.5x+120+(125/x) is 2x-(125)/(x^2)-39.5

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\frac{d}{d x} (x^{2} - 39.5 x + 120 + \frac{125}{x})

2 x - \frac{125}{x ^{2}} - 39.5

Solution steps

\frac{d}{d x} (x^{2} - 39.5 x + 120 + \frac{125}{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) - \frac{d}{d x} (39.5 x) + \frac{d}{d x} (120) + \frac{d}{d x} (\frac{125}{x})

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (39.5 x) = 39.5

\frac{d}{d x} (120) = 0

\frac{d}{d x} (\frac{125}{x}) = - \frac{125}{x ^{2}}

= 2 x - 39.5 + 0 - \frac{125}{x ^{2}}

Simplify

= 2 x - \frac{125}{x ^{2}} - 39.5

x \to 0 - lim (\frac{1}{x ^{3} - x})

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What is the derivative of x^2-39.5x+120+(125/x) ?
The derivative of x^2-39.5x+120+(125/x) is 2x-(125)/(x^2)-39.5
What is the first derivative of x^2-39.5x+120+(125/x) ?
The first derivative of x^2-39.5x+120+(125/x) is 2x-(125)/(x^2)-39.5