What is the integral from 0 to 7 of sqrt(4+3x) ?

The integral from 0 to 7 of sqrt(4+3x) is 26

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integral from 0 to 7 of sqrt(4+3x)

\int_{0}^{7} 4 + 3 x d x

26

Solution steps

\int_{0}^{7} 4 + 3 x d x

Apply u-substitution

: \int_{4}^{25} \frac{u}{3} d u

= \int_{4}^{25} \frac{u}{3} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{3} \cdot \int_{4}^{25} u d u

Apply the Power Rule

: [\frac{2}{3} u^{\frac{3}{2}}]_{4}^{25}

= \frac{1}{3} [\frac{2}{3} u^{\frac{3}{2}}]_{4}^{25}

Compute the boundaries:

78

= \frac{1}{3} \cdot 78

Simplify

= 26

\frac{s}{s ^{2} + 4 s + 13}

x \to 4.2 lim (3)

\int e^{- s t} sin (a t) d t

\int_{- 7}^{9} (\frac{x}{2} + 9) d x

x \to 2 lim (\frac{x}{x})

What is the integral from 0 to 7 of sqrt(4+3x) ?
The integral from 0 to 7 of sqrt(4+3x) is 26