What is the solution for 2x^2y+x^3((dy)/(dx))=1 ?

The solution for 2x^2y+x^3((dy)/(dx))=1 is y=(ln(x))/(x^2)+(c_{1})/(x^2)

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2x^2y+x^3((dy)/(dx))=1

2 x^{2} y + x^{3} (\frac{d y}{d x}) = 1

y = \frac{ln ( x )}{x ^{2}} + \frac{c _{1}}{x ^{2}}

Solution steps

2 x^{2} y + x^{3} (\frac{d y}{d x}) = 1

Solve linear ODE:

y = \frac{ln ( x )}{x ^{2}} + \frac{c _{1}}{x ^{2}}

y = \frac{ln ( x )}{x ^{2}} + \frac{c _{1}}{x ^{2}}

f (x) = \frac{ln ( x )}{x}

x \to 0 lim ((e^{2 x} - 5 x)^{2})

\int \frac{9}{x ( x ^{4} + 8 )} d x

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What is the solution for 2x^2y+x^3((dy)/(dx))=1 ?
The solution for 2x^2y+x^3((dy)/(dx))=1 is y=(ln(x))/(x^2)+(c_{1})/(x^2)