What is the solution for (dy)/(dt)= t/(y+1) ?

The solution for (dy)/(dt)= t/(y+1) is y=-1+sqrt(t^2+c_{1)+1},y=-sqrt(t^2+c_{1)+1}-1

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(dy)/(dt)= t/(y+1)

\frac{d y}{d t} = \frac{t}{y + 1}

y = - 1 + t^{2} + c_{1} + 1, y = - t^{2} + c_{1} + 1 - 1

Solution steps

\frac{d y}{d t} = \frac{t}{y + 1}

Solve separable ODE:

y = - 1 + t^{2} + c_{1} + 1, y = - t^{2} + c_{1} + 1 - 1

y = - 1 + t^{2} + c_{1} + 1, y = - t^{2} + c_{1} + 1 - 1

\frac{d}{d t} (e^{t} (a cos (2 t) + cos (2 t)))

f (x) = - x + \frac{4}{x} + 1

f (x) = - 3 cos (x) - \frac{x ^{2}}{2} + 20

\frac{\partial}{\partial x} (u^{2})

\int \frac{( x ^{3} )}{x - 1} d x

What is the solution for (dy)/(dt)= t/(y+1) ?
The solution for (dy)/(dt)= t/(y+1) is y=-1+sqrt(t^2+c_{1)+1},y=-sqrt(t^2+c_{1)+1}-1