What is the integral of sin(120pix) ?

The integral of sin(120pix) is -1/(120pi)cos(120pix)+C

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integral of sin(120pix)

\int sin (120 π x) d x

- \frac{1}{120 π} cos (120 π x) + C

Solution steps

\int sin (120 π x) d x

Apply u-substitution

: \int sin (u) \frac{1}{120 π} d u

= \int sin (u) \frac{1}{120 π} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{120 π} \cdot \int sin (u) d u

Use the common integral:

\int sin (u) d u = - cos (u)

= \frac{1}{120 π} (- cos (u))

Substitute back

u = 120 π x

= \frac{1}{120 π} (- cos (120 π x))

Simplify

= - \frac{1}{120 π} cos (120 π x)

Add a constant to the solution

= - \frac{1}{120 π} cos (120 π x) + C

f (x) = 4 x^{2} - x^{3}, (1, 3)

y = - x^{2} - 2 x + 2, (- 3, - 1)

sin (x), 0

y^{^{'}} - \frac{9}{x} y = \frac{y ^{5}}{x ^{6}}

n = 1 \sum \infty e^{- 2 n}

What is the integral of sin(120pix) ?
The integral of sin(120pix) is -1/(120pi)cos(120pix)+C