What is the derivative of e^{x^2+x+1} ?

The derivative of e^{x^2+x+1} is e^{x^2+x+1}(2x+1)

What is the first derivative of e^{x^2+x+1} ?

The first derivative of e^{x^2+x+1} is e^{x^2+x+1}(2x+1)

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\frac{d}{d x} (e^{x^{2} + x + 1})

e^{x^{2} + x + 1} (2 x + 1)

Solution steps

\frac{d}{d x} (e^{x^{2} + x + 1})

Apply the chain rule:

e^{x^{2} + x + 1} \frac{d}{d x} (x^{2} + x + 1)

= e^{x^{2} + x + 1} \frac{d}{d x} (x^{2} + x + 1)

\frac{d}{d x} (x^{2} + x + 1) = 2 x + 1

= e^{x^{2} + x + 1} (2 x + 1)

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\frac{d}{d t} (\frac{t ^{4}}{4})

\frac{d}{d x} (x^{- \frac{2}{5}})

y^{^{''}} + 529 y = sec (23 x)

\frac{d}{d x} (2 cos (- 6 x))

What is the derivative of e^{x^2+x+1} ?
The derivative of e^{x^2+x+1} is e^{x^2+x+1}(2x+1)
What is the first derivative of e^{x^2+x+1} ?
The first derivative of e^{x^2+x+1} is e^{x^2+x+1}(2x+1)