What is area 4x^4-4x^2,3x^2,[0,0] ?

The answer to area 4x^4-4x^2,3x^2,[0,0] is (49sqrt(7))/(30)

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area 4x^4-4x^2,3x^2,[0,0]

area

4 x^{4} - 4 x^{2}, 3 x^{2}, [0, 0]

\frac{49 7}{30}

Decimal Notation

4.32139 \dots

Solution steps

Apply the area formula:

\int_{- \frac{7}{2}}^{\frac{7}{2}} 4 x^{4} - 7 x^{2} d x

Solve

\int_{- \frac{7}{2}}^{\frac{7}{2}} 4 x^{4} - 7 x^{2} d x : \frac{49 7}{30}

The area is:

= \frac{49 7}{30}

n = 1 \sum \infty cos^{n} (1.6)

\frac{d}{d x} (e^{x} x^{2})

x^{7} arcsin (x)

\int (5 x^{2} + 7 x + 11) d x

\int_{0}^{\frac{1}{2}} x cos (π x) d x

What is area 4x^4-4x^2,3x^2,[0,0] ?
The answer to area 4x^4-4x^2,3x^2,[0,0] is (49sqrt(7))/(30)