What is the integral of sin(wt) ?

The integral of sin(wt) is -1/w cos(wt)+C

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integral of sin(wt)

\int sin (wt) d t

- \frac{1}{w} cos (wt) + C

Solution steps

\int sin (wt) d t

Apply u-substitution

: \int \frac{sin ( u )}{w} d u

= \int \frac{sin ( u )}{w} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{w} \cdot \int sin (u) d u

Use the common integral:

\int sin (u) d u = - cos (u)

= \frac{1}{w} (- cos (u))

Substitute back

u = wt

= \frac{1}{w} (- cos (wt))

Simplify

= - \frac{1}{w} cos (wt)

Add a constant to the solution

= - \frac{1}{w} cos (wt) + C

x y^{^{'}} = \frac{1}{y ^{3}}

\int_{- 1}^{2} (- x^{2} + x + 2)^{2} d x

x \to \infty lim (\frac{x}{0})

(t^{2} + x^{2}) d t + t x d x = 0