What is the integral from 2 to 5 of 1/(x^2) ?

The integral from 2 to 5 of 1/(x^2) is 3/10

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integral from 2 to 5 of 1/(x^2)

\int_{2}^{5} \frac{1}{x ^{2}} d x

\frac{3}{10}

Decimal Notation

0.3

Solution steps

\int_{2}^{5} \frac{1}{x ^{2}} d x

Apply the Power Rule

: [- \frac{1}{x}]_{2}^{5}

= [- \frac{1}{x}]_{2}^{5}

Compute the boundaries:

\frac{3}{10}

= \frac{3}{10}

\int_{0}^{2} \frac{( 4 x + 3 )}{x ^{4}} d x

\frac{d}{d x} (a sin^{3} (\frac{x}{3}))

y^{^{'}} + \frac{y}{x} = \frac{e ^{x}}{x}

5 x + 4, at x = 9

\frac{d}{d x} (2 arccos (x))

What is the integral from 2 to 5 of 1/(x^2) ?
The integral from 2 to 5 of 1/(x^2) is 3/10