What is area y=10+9x-x^2,y=-3x+46,[6,15+1/3 ] ?

The answer to area y=10+9x-x^2,y=-3x+46,[6,15+1/3 ] is 21952/81

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area y=10+9x-x^2,y=-3x+46,[6,15+1/3 ]

area

y = 10 + 9 x - x^{2}, y = - 3 x + 46, [6, 15 + \frac{1}{3}]

\frac{21952}{81}

Decimal Notation

271.01234 \dots

Solution steps

Apply the area formula:

\int_{6}^{15 + \frac{1}{3}} 10 + 9 x - x^{2} - (- 3 x + 46) d x

Solve

\int_{6}^{15 + \frac{1}{3}} 10 + 9 x - x^{2} - (- 3 x + 46) d x : \frac{21952}{81}

The area is:

= \frac{21952}{81}

t y^{^{'}} = t^{3} + 7 t^{3} y

\frac{d}{d x} (tan (x) + cot (x))

\int \frac{9 + x}{x} d x

y^{^{'}} = - \frac{4 x}{y}

n = 0 \sum \infty \frac{8}{n !}

What is area y=10+9x-x^2,y=-3x+46,[6,15+1/3 ] ?
The answer to area y=10+9x-x^2,y=-3x+46,[6,15+1/3 ] is 21952/81