What is the derivative of 3x-ln(3x+1) ?

The derivative of 3x-ln(3x+1) is 3-3/(3x+1)

What is the first derivative of 3x-ln(3x+1) ?

The first derivative of 3x-ln(3x+1) is 3-3/(3x+1)

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\frac{d}{d x} (3 x - ln (3 x + 1))

3 - \frac{3}{3 x + 1}

Solution steps

\frac{d}{d x} (3 x - ln (3 x + 1))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x) - \frac{d}{d x} (ln (3 x + 1))

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (ln (3 x + 1)) = \frac{3}{3 x + 1}

= 3 - \frac{3}{3 x + 1}

2 x, x

x \to 0 lim (6)

\frac{d}{d x} (10 - 10 e^{- 2 x})

x \to 1 + lim (\frac{1}{x + 1})

x^{2} sin^{8} (x) + x cos^{- 5} (x)

What is the derivative of 3x-ln(3x+1) ?
The derivative of 3x-ln(3x+1) is 3-3/(3x+1)
What is the first derivative of 3x-ln(3x+1) ?
The first derivative of 3x-ln(3x+1) is 3-3/(3x+1)