What is the derivative of 1/3 (e^{3-x}) ?

The derivative of 1/3 (e^{3-x}) is -1/3 e^{3-x}

What is the first derivative of 1/3 (e^{3-x}) ?

The first derivative of 1/3 (e^{3-x}) is -1/3 e^{3-x}

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\frac{d}{d x} (\frac{1}{3} (e^{3 - x}))

- \frac{1}{3} e^{3 - x}

Solution steps

\frac{d}{d x} (\frac{1}{3} (e^{3 - x}))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{3} \frac{d}{d x} (e^{3 - x})

Apply the chain rule:

e^{3 - x} \frac{d}{d x} (3 - x)

= e^{3 - x} \frac{d}{d x} (3 - x)

\frac{d}{d x} (3 - x) = - 1

= \frac{1}{3} e^{3 - x} (- 1)

Simplify

= - \frac{1}{3} e^{3 - x}

\frac{\partial}{\partial x} (\frac{3 x - 3 z}{2 y + 3 z})

n = 0 \sum \infty n + 1

\int (6 x^{2} - 6 x + 2) d x

\frac{e ^{x}}{7 + e ^{x}}

\frac{d ^{2}}{d x ^{2}} (\frac{1}{x - 1})

What is the derivative of 1/3 (e^{3-x}) ?
The derivative of 1/3 (e^{3-x}) is -1/3 e^{3-x}
What is the first derivative of 1/3 (e^{3-x}) ?
The first derivative of 1/3 (e^{3-x}) is -1/3 e^{3-x}