What is the derivative of y=(x^5+1)^7 ?

The derivative of y=(x^5+1)^7 is 35x^4(x^5+1)^6

What is the first derivative of y=(x^5+1)^7 ?

The first derivative of y=(x^5+1)^7 is 35x^4(x^5+1)^6

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derivative of

y = (x^{5} + 1)^{7}

35 x^{4} (x^{5} + 1)^{6}

Solution steps

\frac{d}{d x} ((x^{5} + 1)^{7})

Apply the chain rule:

7 (x^{5} + 1)^{6} \frac{d}{d x} (x^{5} + 1)

= 7 (x^{5} + 1)^{6} \frac{d}{d x} (x^{5} + 1)

\frac{d}{d x} (x^{5} + 1) = 5 x^{4}

= 7 (x^{5} + 1)^{6} \cdot 5 x^{4}

Simplify

= 35 x^{4} (x^{5} + 1)^{6}

\frac{d y}{d x} - y = 2 e^{x} y^{2}

\int t \cdot sin (t) d t

\frac{1}{( s + 1 ) ^{4}}

\frac{\partial}{\partial x} (y e^{6 x})

f (x) = (3) e^{- 5 x}

What is the derivative of y=(x^5+1)^7 ?
The derivative of y=(x^5+1)^7 is 35x^4(x^5+1)^6
What is the first derivative of y=(x^5+1)^7 ?
The first derivative of y=(x^5+1)^7 is 35x^4(x^5+1)^6