What is (\partial)/(\partial x)(e^{-x}sin(yz)) ?

The answer to (\partial)/(\partial x)(e^{-x}sin(yz)) is -e^{-x}sin(yz)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)(e^{-x}sin(yz))

\frac{\partial}{\partial x} (e^{- x} sin (yz))

- e^{- x} sin (yz)

Solution steps

\frac{\partial}{\partial x} (e^{- x} sin (yz))

Treat

y, z

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= sin (yz) \frac{\partial}{\partial x} (e^{- x})

Apply the chain rule:

e^{- x} \frac{\partial}{\partial x} (- x)

= e^{- x} \frac{\partial}{\partial x} (- x)

\frac{\partial}{\partial x} (- x) = - 1

= sin (yz) e^{- x} (- 1)

Simplify

= - e^{- x} sin (yz)

f (x) = 2 x^{5} - 6 x^{3}, at x = 1

\int ln (d) x d x

x \to 3 lim (\frac{x - 1}{x ^{2}})

y = x^{2} + x - 2, y = 0

\int \frac{1}{( x - 1 ) ( 2 - x )} d x

What is (\partial)/(\partial x)(e^{-x}sin(yz)) ?
The answer to (\partial)/(\partial x)(e^{-x}sin(yz)) is -e^{-x}sin(yz)