What is the derivative of y=6x^3-x^2 ?

The derivative of y=6x^3-x^2 is 18x^2-2x

What is the first derivative of y=6x^3-x^2 ?

The first derivative of y=6x^3-x^2 is 18x^2-2x

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derivative of

y = 6 x^{3} - x^{2}

18 x^{2} - 2 x

Solution steps

\frac{d}{d x} (6 x^{3} - x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (6 x^{3}) - \frac{d}{d x} (x^{2})

\frac{d}{d x} (6 x^{3}) = 18 x^{2}

\frac{d}{d x} (x^{2}) = 2 x

= 18 x^{2} - 2 x

f (x) = 2 x^{3} + 3 x^{2} - 12 x + 6, at x = 0

e^{x} \cdot x

f (x) = - \frac{12 x}{( x ^{2} + 2 ) ^{\frac{5}{2}}}

n = 1 \sum \infty \frac{1}{n !}

\frac{d}{d x} (2 x sin (3 x))

What is the derivative of y=6x^3-x^2 ?
The derivative of y=6x^3-x^2 is 18x^2-2x
What is the first derivative of y=6x^3-x^2 ?
The first derivative of y=6x^3-x^2 is 18x^2-2x