What is the solution for y^{'''}+6y^{''}+9y^'=0 ?

The solution for y^{'''}+6y^{''}+9y^'=0 is y=c_{1}+c_{2}e^{-3t}+c_{3}te^{-3t}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{'''}+6y^{''}+9y^'=0

y^{^{'''}} + 6 y^{^{''}} + 9 y^{^{'}} = 0

y = c_{1} + c_{2} e^{- 3 t} + c_{3} t e^{- 3 t}

Solution steps

y^{'''} (t) + 6 y^{''} (t) + 9 y^{'} (t) = 0

Solve linear ODE:

y = c_{1} + c_{2} e^{- 3 t} + c_{3} t e^{- 3 t}

y = c_{1} + c_{2} e^{- 3 t} + c_{3} t e^{- 3 t}

\int_{1}^{6} \frac{2}{x - 11} d x

\frac{d x}{d t} + 4 \cdot 1 0^{- 4} x = 8 \cdot 1 0^{- 5}, x (0) = 1

f (x) = 3 x^{2} - 5 x + 1

(4 x - 3)^{\frac{1}{2}}

ln (1 + x), 0

What is the solution for y^{'''}+6y^{''}+9y^'=0 ?
The solution for y^{'''}+6y^{''}+9y^'=0 is y=c_{1}+c_{2}e^{-3t}+c_{3}te^{-3t}