What is the integral from 0 to 1 of 3x^3 ?

The integral from 0 to 1 of 3x^3 is 3/4

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integral from 0 to 1 of 3x^3

\int_{0}^{1} 3 x^{3} d x

\frac{3}{4}

Decimal

0.75

Solution steps

\int_{0}^{1} 3 x^{3} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int_{0}^{1} x^{3} d x

Apply the Power Rule

: [\frac{x ^{4}}{4}]_{0}^{1}

= 3 [\frac{x ^{4}}{4}]_{0}^{1}

Compute the boundaries:

\frac{1}{4}

= 3 \cdot \frac{1}{4}

Simplify

= \frac{3}{4}

\int_{0}^{2} - x^{2} + 4 d x

\frac{d}{d y} (x e^{- y})

\int sin^{4} (x co) s^{5} x d x

h \to 0 lim (\frac{( 1 + h ) ^{5} - 1}{h})

\int \frac{t ^{2}}{t} d t

What is the integral from 0 to 1 of 3x^3 ?
The integral from 0 to 1 of 3x^3 is 3/4