What is the integral from 10 to 20 of (10)/(x^2) ?

The integral from 10 to 20 of (10)/(x^2) is 1/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 10 to 20 of (10)/(x^2)

\int_{10}^{20} \frac{10}{x ^{2}} d x

\frac{1}{2}

Decimal

0.5

Solution steps

\int_{10}^{20} \frac{10}{x ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 10 \cdot \int_{10}^{20} \frac{1}{x ^{2}} d x

Apply the Power Rule

: [- \frac{1}{x}]_{10}^{20}

= 10 [- \frac{1}{x}]_{10}^{20}

Compute the boundaries:

\frac{1}{20}

= 10 \cdot \frac{1}{20}

Simplify

= \frac{1}{2}

\int 4 x^{2} (4 x^{3} - x^{2})^{6} d x

y^{^{''}} + y^{^{'}} - 6 y = t e^{2 t}

\frac{\partial}{\partial x} (1 + \frac{2}{y})

\int_{0}^{34} (2 x - x^{2}) d x

x^{2} \frac{d ^{2} y}{d x ^{2}} - 7 x \frac{d y}{d x} + 16 y = 0

What is the integral from 10 to 20 of (10)/(x^2) ?
The integral from 10 to 20 of (10)/(x^2) is 1/2