What is the tangent of 4-11x+6x^2 ?

The tangent of 4-11x+6x^2 is y=(12a_{0}-11)x-6a_{0}^2+4

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tangent of 4-11x+6x^2

tangent of

4 - 11 x + 6 x^{2}

y = (12 a_{0} - 11) x - 6 a_{0}^{2} + 4

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, 4 - 11 a_{0} + 6 a_{0}^{2})

Find the slope of

y = 4 - 11 x + 6 x^{2} : \frac{d y}{d x} = 12 x - 11

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 12 a_{0} - 11

Find the line with slope m=

12 a_{0} - 11

and passing through

(a_{0}, 4 - 11 a_{0} + 6 a_{0}^{2}) : y = (12 a_{0} - 11) x - 6 a_{0}^{2} + 4

y = (12 a_{0} - 11) x - 6 a_{0}^{2} + 4

x 3 + y 3 - 6 x y = 0

\int \frac{1}{2 + 4 x ^{2}} d x

n = 0 \sum \infty sin (π \cdot n)

\frac{d}{d x} (6 x x)

x \to - \infty lim (3^{x} x)

What is the tangent of 4-11x+6x^2 ?
The tangent of 4-11x+6x^2 is y=(12a_{0}-11)x-6a_{0}^2+4