What is the derivative of 4x^{-2} ?

The derivative of 4x^{-2} is -8/(x^3)

What is the first derivative of 4x^{-2} ?

The first derivative of 4x^{-2} is -8/(x^3)

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derivative of

4 x^{- 2}

- \frac{8}{x ^{3}}

Solution steps

\frac{d}{d x} (4 x^{- 2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 \frac{d}{d x} (x^{- 2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 4 (- 2 x^{- 2 - 1})

Simplify

4 (- 2 x^{- 2 - 1}) : - \frac{8}{x ^{3}}

= - \frac{8}{x ^{3}}

\frac{\partial}{\partial x} (\frac{y}{y + 4})

\int \frac{x ^{'}}{x ^{2} + 1} d x

\int x^{17} sin (x^{18}) d x

g (t) = \frac{1 - 3 t}{4 + t}

f (x) = \frac{1}{x ^{3} + 2 x ^{2} - 1}

What is the derivative of 4x^{-2} ?
The derivative of 4x^{-2} is -8/(x^3)
What is the first derivative of 4x^{-2} ?
The first derivative of 4x^{-2} is -8/(x^3)