What is the tangent of y=9-2x^2,(2,1) ?

The tangent of y=9-2x^2,(2,1) is y=-8x+17

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tangent of y=9-2x^2,(2,1)

tangent of

y = 9 - 2 x^{2}, (2, 1)

y = - 8 x + 17

Solution steps

Find the slope of

y = 9 - 2 x^{2} : \frac{d y}{d x} = - 4 x

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 8

Find the line with slope m=

- 8

and passing through

(2, 1) : y = - 8 x + 17

y = - 8 x + 17

\int_{0}^{\frac{3 π}{2}} cos^{3} (21 x) d x

\frac{x}{10 - 9 x}

\int (25 - x^{2})^{- \frac{3}{2}} d x

\frac{d}{d x} (1 0^{2 x})

\frac{d b}{d b}

What is the tangent of y=9-2x^2,(2,1) ?
The tangent of y=9-2x^2,(2,1) is y=-8x+17