What is the integral of sqrt(1-sin^2(x)) ?

The integral of sqrt(1-sin^2(x)) is sin(x)+C

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integral of sqrt(1-sin^2(x))

\int 1 - sin^{2} (x) d x

sin (x) + C

Solution steps

\int 1 - sin^{2} (x) d x

Rewrite using trig identities

= \int cos^{2} (x) d x

cos^{2} (x) = (cos (x)),

assuming

cos (x) \geq 0

= \int cos (x) d x

Use the common integral:

\int cos (x) d x = sin (x)

= sin (x)

Add a constant to the solution

= sin (x) + C

\frac{d}{d x} (16 + x)

x \to 0 lim (2^{- x})

\int_{1}^{2} x - 1 - x + 1 d x

f (x) = x^{s i n (x)}, (\frac{π}{2}, \frac{π}{2})

\int x^{2} (x^{3} - 1)^{3} d x

What is the integral of sqrt(1-sin^2(x)) ?
The integral of sqrt(1-sin^2(x)) is sin(x)+C