What is (\partial)/(\partial x)(sin(3x+2y)) ?

The answer to (\partial)/(\partial x)(sin(3x+2y)) is cos(3x+2y)*3

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(\partial)/(\partial x)(sin(3x+2y))

\frac{\partial}{\partial x} (sin (3 x + 2 y))

cos (3 x + 2 y) \cdot 3

Solution steps

\frac{\partial}{\partial x} (sin (3 x + 2 y))

Treat

y

as a constant

Apply the chain rule:

cos (3 x + 2 y) \frac{\partial}{\partial x} (3 x + 2 y)

= cos (3 x + 2 y) \frac{\partial}{\partial x} (3 x + 2 y)

\frac{\partial}{\partial x} (3 x + 2 y) = 3

= cos (3 x + 2 y) \cdot 3

\frac{s}{( s ^{2} + 16 ) ^{2}}

4 y^{^{''}} + 6 y^{^{'}} + 7 y = 0

\frac{d}{d x} ((4 x - x^{2})^{100})

\frac{d}{d x} (sin (e^{2 x y}) + e^{s i n (2 x y)})

y = 4 x + 33, (4, 7)

What is (\partial)/(\partial x)(sin(3x+2y)) ?
The answer to (\partial)/(\partial x)(sin(3x+2y)) is cos(3x+2y)*3