What is the derivative of 2x^2+8x+10 ?

The derivative of 2x^2+8x+10 is 4x+8

What is the first derivative of 2x^2+8x+10 ?

The first derivative of 2x^2+8x+10 is 4x+8

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\frac{d}{d x} (2 x^{2} + 8 x + 10)

4 x + 8

Solution steps

\frac{d}{d x} (2 x^{2} + 8 x + 10)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{2}) + \frac{d}{d x} (8 x) + \frac{d}{d x} (10)

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (8 x) = 8

\frac{d}{d x} (10) = 0

= 4 x + 8 + 0

Simplify

= 4 x + 8

x \to - 3 lim (7 + x)

x \to - 3 lim (x + 3)

\frac{( x + 1 ) ( x + 2 )}{( x - 1 ) ( x - 2 )}

\int [tan (5 x) + csc^{3} (3 θ)] d θ

f (x) = \frac{e ^{x}}{x}, (1, e)

What is the derivative of 2x^2+8x+10 ?
The derivative of 2x^2+8x+10 is 4x+8
What is the first derivative of 2x^2+8x+10 ?
The first derivative of 2x^2+8x+10 is 4x+8