What is (\partial)/(\partial y)(4x^2y^2) ?

The answer to (\partial)/(\partial y)(4x^2y^2) is 8x^2y

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(\partial)/(\partial y)(4x^2y^2)

\frac{\partial}{\partial y} (4 x^{2} y^{2})

8 x^{2} y

Solution steps

\frac{\partial}{\partial y} (4 x^{2} y^{2})

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 x^{2} \frac{\partial}{\partial y} (y^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 4 x^{2} \cdot 2 y^{2 - 1}

Simplify

= 8 x^{2} y

f (x) = 6 x

cos (x) (\frac{d y}{d x}) - sin (x) y = 0

x \to 1 lim (\frac{3}{x ^{2}})

\int x arctan (21 x) d x

y^{^{'}} - 2 x y = x^{3} y^{5}

What is (\partial)/(\partial y)(4x^2y^2) ?
The answer to (\partial)/(\partial y)(4x^2y^2) is 8x^2y