What is the derivative of f(x)=-3x^3+2x^2-4x+7 ?

The derivative of f(x)=-3x^3+2x^2-4x+7 is -9x^2+4x-4

What is the first derivative of f(x)=-3x^3+2x^2-4x+7 ?

The first derivative of f(x)=-3x^3+2x^2-4x+7 is -9x^2+4x-4

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derivative of

f (x) = - 3 x^{3} + 2 x^{2} - 4 x + 7

- 9 x^{2} + 4 x - 4

Solution steps

\frac{d}{d x} (- 3 x^{3} + 2 x^{2} - 4 x + 7)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (3 x^{3}) + \frac{d}{d x} (2 x^{2}) - \frac{d}{d x} (4 x) + \frac{d}{d x} (7)

\frac{d}{d x} (3 x^{3}) = 9 x^{2}

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (4 x) = 4

\frac{d}{d x} (7) = 0

= - 9 x^{2} + 4 x - 4 + 0

Simplify

= - 9 x^{2} + 4 x - 4

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What is the derivative of f(x)=-3x^3+2x^2-4x+7 ?
The derivative of f(x)=-3x^3+2x^2-4x+7 is -9x^2+4x-4
What is the first derivative of f(x)=-3x^3+2x^2-4x+7 ?
The first derivative of f(x)=-3x^3+2x^2-4x+7 is -9x^2+4x-4