What is the derivative of 3x^2-6x+7 ?

The derivative of 3x^2-6x+7 is 6x-6

What is the first derivative of 3x^2-6x+7 ?

The first derivative of 3x^2-6x+7 is 6x-6

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\frac{d}{d x} (3 x^{2} - 6 x + 7)

6 x - 6

Solution steps

\frac{d}{d x} (3 x^{2} - 6 x + 7)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{2}) - \frac{d}{d x} (6 x) + \frac{d}{d x} (7)

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (6 x) = 6

\frac{d}{d x} (7) = 0

= 6 x - 6 + 0

Simplify

= 6 x - 6

\frac{x + 1}{x ^{2} + 1}

\frac{d}{d x} (x e^{x^{6}})

2 (12) (18) + 2 (9)

\frac{d r}{d θ} = 8 cos (θ)

\int 92

What is the derivative of 3x^2-6x+7 ?
The derivative of 3x^2-6x+7 is 6x-6
What is the first derivative of 3x^2-6x+7 ?
The first derivative of 3x^2-6x+7 is 6x-6