What is (\partial)/(\partial x)(5ycos(x)) ?

The answer to (\partial)/(\partial x)(5ycos(x)) is -5ysin(x)

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(\partial)/(\partial x)(5ycos(x))

\frac{\partial}{\partial x} (5 y cos (x))

- 5 y sin (x)

Solution steps

\frac{\partial}{\partial x} (5 y cos (x))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 5 y \frac{\partial}{\partial x} (cos (x))

Apply the common derivative:

\frac{\partial}{\partial x} (cos (x)) = - sin (x)

= 5 y (- sin (x))

Simplify

= - 5 y sin (x)

\int e^{\frac{1}{2} l n (x)} d x

n = 1 \sum \infty \frac{1}{2} (\frac{1}{2})^{n}

y^{^{'}} = \frac{( e ^{x} )}{e ^{y}}, y (0) = 2

n = 0 \sum \infty \frac{1}{n ^{2} + 9 n + 20}

f (x) = x^{2} - 2 x + 3

What is (\partial)/(\partial x)(5ycos(x)) ?
The answer to (\partial)/(\partial x)(5ycos(x)) is -5ysin(x)