What is the integral of 5\sqrt[4]{x} ?

The integral of 5\sqrt[4]{x} is 4x^{5/4}+C

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integral of 5\sqrt[4]{x}

\int 5 4 x d x

4 x^{\frac{5}{4}} + C

Solution steps

\int 5 4 x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 5 \cdot \int 4 x d x

Apply the Power Rule

: \frac{4}{5} x^{\frac{5}{4}}

= 5 \cdot \frac{4}{5} x^{\frac{5}{4}}

Simplify

5 \cdot \frac{4}{5} x^{\frac{5}{4}} : 4 x^{\frac{5}{4}}

= 4 x^{\frac{5}{4}}

Add a constant to the solution

= 4 x^{\frac{5}{4}} + C

4^{2}

x \to - 2 lim (- x)

\frac{d}{d x} (\frac{y}{( x ^{2} + y ^{2} )})

5^{x}

y^{^{'}} - 2 x y = 0

What is the integral of 5\sqrt[4]{x} ?
The integral of 5\sqrt[4]{x} is 4x^{5/4}+C