What is the integral of 14cot^4(x) ?

The integral of 14cot^4(x) is 14(-1/3 cot^3(x)+x+cot(x))+C

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integral of 14cot^4(x)

\int 14 cot^{4} (x) d x

14 (- \frac{1}{3} cot^{3} (x) + x + cot (x)) + C

Solution steps

\int 14 cot^{4} (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 14 \cdot \int cot^{4} (x) d x

Apply Integral Reduction

= 14 (- \frac{cot ^{3} ( x )}{3} - \int cot^{2} (x) d x)

\int cot^{2} (x) d x = - x - cot (x)

= 14 (- \frac{cot ^{3} ( x )}{3} - (- x - cot (x)))

Simplify

14 (- \frac{cot ^{3} ( x )}{3} - (- x - cot (x))) : 14 (- \frac{1}{3} cot^{3} (x) + x + cot (x))

= 14 (- \frac{1}{3} cot^{3} (x) + x + cot (x))

Add a constant to the solution

= 14 (- \frac{1}{3} cot^{3} (x) + x + cot (x)) + C

\int \frac{2}{e ^{3 x}} d x

\frac{d}{d x} (4^{s i n (2) (x) + c o s (3 x)})

\int \frac{1}{1 - 4 t ^{2}} d t

y^{^{'}} = 0.2 ln (\frac{4000}{y}) y

\int_{0}^{1} 2

What is the integral of 14cot^4(x) ?
The integral of 14cot^4(x) is 14(-1/3 cot^3(x)+x+cot(x))+C