What is the tangent of 7x^2-9x,\at x=-17 ?

The tangent of 7x^2-9x,\at x=-17 is y=-247x-2023

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tangent of 7x^2-9x,\at x=-17

tangent of

7 x^{2} - 9 x, at x = - 17

y = - 247 x - 2023

Solution steps

Find the tangent point:

(- 17, 2176)

Find the slope of

y = 7 x^{2} - 9 x : \frac{d y}{d x} = 14 x - 9

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 247

Find the line with slope m=

- 247

and passing through

(- 17, 2176) : y = - 247 x - 2023

y = - 247 x - 2023

f (x) = 2 x^{2} - 5 x + 3, at x = 1

\int \frac{( 3 + 4 x )}{3 x - x ^{2} - 2} d x

x \to 3 lim (\frac{x + 3}{x + 6})

\int \frac{1}{t ^{2} - 10 t + 41} d t

f (x) = x^{2} arctan (5 x)

What is the tangent of 7x^2-9x,\at x=-17 ?
The tangent of 7x^2-9x,\at x=-17 is y=-247x-2023