What is the integral of 10000(t-6) ?

The integral of 10000(t-6) is 10000((t^2)/2-6t)+C

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integral of 10000(t-6)

\int 10000 (t - 6) d t

10000 (\frac{t ^{2}}{2} - 6 t) + C

Solution steps

\int 10000 (t - 6) d t

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 10000 \cdot \int t - 6 d t

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= 10000 (\int t d t - \int 6 d t)

\int t d t = \frac{t ^{2}}{2}

\int 6 d t = 6 t

= 10000 (\frac{t ^{2}}{2} - 6 t)

Add a constant to the solution

= 10000 (\frac{t ^{2}}{2} - 6 t) + C

\int 5 x sin (x) d x

14 x

5 - 2 t

f (x) = e^{l n (c o s (x^{2}))} 2 x + 1

\int_{0}^{4} (16 x^{2} - x^{4}) d x

What is the integral of 10000(t-6) ?
The integral of 10000(t-6) is 10000((t^2)/2-6t)+C