What is the solution for (1+y)dx+(1-x)dy=0 ?

The solution for (1+y)dx+(1-x)dy=0 is y=e^{-c_{1}}-e^{-c_{1}}x-1

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(1+y)dx+(1-x)dy=0

(1 + y) d x + (1 - x) d y = 0

y = e^{- c_{1}} - e^{- c_{1}} x - 1

Solution steps

(1 + y) d x + (1 - x) d y = 0

Solve separable ODE:

y = e^{- c_{1}} - e^{- c_{1}} x - 1

y = e^{- c_{1}} - e^{- c_{1}} x - 1

y^{^{'}} = y ln (\frac{1}{y})

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What is the solution for (1+y)dx+(1-x)dy=0 ?
The solution for (1+y)dx+(1-x)dy=0 is y=e^{-c_{1}}-e^{-c_{1}}x-1