What is the integral of ((cos(x))^2)/2 ?

The integral of ((cos(x))^2)/2 is 1/4 (x+1/2 sin(2x))+C

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integral of ((cos(x))^2)/2

\int \frac{( cos ( x ) ) ^{2}}{2} d x

\frac{1}{4} (x + \frac{1}{2} sin (2 x)) + C

Solution steps

\int \frac{( cos ( x ) ) ^{2}}{2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int (cos (x))^{2} d x

Simplify

= \frac{1}{2} \cdot \int cos^{2} (x) d x

Rewrite using trig identities

= \frac{1}{2} \cdot \int \frac{1 + cos ( 2 x )}{2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \frac{1}{2} \cdot \int 1 + cos (2 x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \frac{1}{2} \cdot \frac{1}{2} (\int 1 d x + \int cos (2 x) d x)

\int 1 d x = x

\int cos (2 x) d x = \frac{1}{2} sin (2 x)

= \frac{1}{2} \cdot \frac{1}{2} (x + \frac{1}{2} sin (2 x))

Simplify

\frac{1}{2} \cdot \frac{1}{2} (x + \frac{1}{2} sin (2 x)) : \frac{1}{4} (x + \frac{1}{2} sin (2 x))

= \frac{1}{4} (x + \frac{1}{2} sin (2 x))

Add a constant to the solution

= \frac{1}{4} (x + \frac{1}{2} sin (2 x)) + C

\int sin^{4} (x) \cdot cos^{2} (x) d x

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\int 2 x - \frac{1}{e ^{x^{2}}} d x

14 (4 e^{x^{2}} x^{3} + 6 e^{x^{2}} x)

(x + 7) \cdot ln (x)

What is the integral of ((cos(x))^2)/2 ?
The integral of ((cos(x))^2)/2 is 1/4 (x+1/2 sin(2x))+C