What is area y=x-3,y=-sqrt(x-1),x=1,x=3 ?

The answer to area y=x-3,y=-sqrt(x-1),x=1,x=3 is (4sqrt(2)-1)/3

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area y=x-3,y=-sqrt(x-1),x=1,x=3

area

y = x - 3, y = - x - 1, x = 1, x = 3

\frac{4 2 - 1}{3}

Decimal

1.55228 \dots

Solution steps

Apply the area formula:

\int_{1}^{3} x - 3 + x - 1 d x

Solve

\int_{1}^{3} x - 3 + x - 1 d x : \frac{4 2 - 1}{3}

The area is:

= \frac{4 2 - 1}{3}

x^{\frac{9}{6}}, 8

(9 - x^{3})^{5}

\int \frac{4}{5} - \frac{9}{x} d x

f (2) = 2 x^{3} - 1

\frac{d}{d x} (0.01 x^{3})

What is area y=x-3,y=-sqrt(x-1),x=1,x=3 ?
The answer to area y=x-3,y=-sqrt(x-1),x=1,x=3 is (4sqrt(2)-1)/3