What is the limit as h approaches 0 of 5x^2+8y^2 ?

The limit as h approaches 0 of 5x^2+8y^2 is 5x^2+8y^2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as h approaches 0 of 5x^2+8y^2

h \to 0 lim (5 x^{2} + 8 y^{2})

5 x^{2} + 8 y^{2}

Solution steps

h \to 0 lim (5 x^{2} + 8 y^{2})

x \to a lim c = c

= 5 x^{2} + 8 y^{2}

n = 0 \sum \infty (2 n)! (\frac{x}{3})^{n}

\frac{1}{( 5 s ^{2} + s )}

\frac{d}{d x} (\frac{x ^{2} + 1}{x - 9})

\frac{\partial}{\partial x} (2 (x + y))

\int (1 + y) d y

What is the limit as h approaches 0 of 5x^2+8y^2 ?
The limit as h approaches 0 of 5x^2+8y^2 is 5x^2+8y^2