What is the solution for (-x+2)*y^'-y=e^{-2x} ?

The solution for (-x+2)*y^'-y=e^{-2x} is y=-(e^{-2x})/(2(-x+2))+(c_{1})/(-x+2)

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(-x+2)*y^'-y=e^{-2x}

(- x + 2) \cdot y^{^{'}} - y = e^{- 2 x}

y = - \frac{e ^{- 2 x}}{2 ( - x + 2 )} + \frac{c _{1}}{- x + 2}

Solution steps

(- x + 2) \cdot y^{'} (x) - y = e^{- 2 x}

Solve linear ODE:

y = - \frac{e ^{- 2 x}}{2 ( - x + 2 )} + \frac{c _{1}}{- x + 2}

y = - \frac{e ^{- 2 x}}{2 ( - x + 2 )} + \frac{c _{1}}{- x + 2}

\frac{d y}{d x} = a (y^{2} + 1)

\frac{d}{d x} (\frac{x ^{2}}{1 - x ^{2}})

\frac{d y}{d x} = (1 + x) (1 + y^{2})

\frac{e ^{- s}}{s - 5}

\frac{d}{d x} (\frac{( x - 1 ) ^{2}}{x ^{2}})

What is the solution for (-x+2)*y^'-y=e^{-2x} ?
The solution for (-x+2)*y^'-y=e^{-2x} is y=-(e^{-2x})/(2(-x+2))+(c_{1})/(-x+2)