What is the derivative of-(x^4)/(y^4) ?

The derivative of-(x^4)/(y^4) is -(4x^3)/(y^4)

What is the first derivative of-(x^4)/(y^4) ?

The first derivative of-(x^4)/(y^4) is -(4x^3)/(y^4)

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derivative of

- \frac{x ^{4}}{y ^{4}}

- \frac{4 x ^{3}}{y ^{4}}

Solution steps

\frac{d}{d x} (- \frac{x ^{4}}{y ^{4}})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - \frac{1}{y ^{4}} \frac{d}{d x} (x^{4})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= - \frac{1}{y ^{4}} \cdot 4 x^{4 - 1}

Simplify

- \frac{1}{y ^{4}} \cdot 4 x^{4 - 1} : - \frac{4 x ^{3}}{y ^{4}}

= - \frac{4 x ^{3}}{y ^{4}}

\int (sin^{2} (3 x)) d x

\int 4 x^{2} (4 x^{3} + 5)^{5} d x

ln (3 \frac{3 x}{x + 2})

\int - z^{2} d z

\frac{\partial}{\partial x} (y \cdot e^{\frac{x}{y}})

What is the derivative of-(x^4)/(y^4) ?
The derivative of-(x^4)/(y^4) is -(4x^3)/(y^4)
What is the first derivative of-(x^4)/(y^4) ?
The first derivative of-(x^4)/(y^4) is -(4x^3)/(y^4)